What is the domain of f(x)=(\sqrt[4]{3x-2})/(x-5)+x ?

The domain of f(x)=(\sqrt[4]{3x-2})/(x-5)+x is 2/3 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(\sqrt[4]{3x-2})/(x-5)+x

domain

\frac{2}{3} \leq x < 5 or x > 5

Interval Notation

[\frac{2}{3}, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{2}{3}

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

\frac{2}{3} \leq x < 5 or x > 5

f (x) = \frac{1}{z}

f (x) = \frac{x ^{2}}{2} + \frac{1}{x}

f (x) = ln (12 - 5 x^{2})

y = ln (ln (3 x - 14))

y = 3 tan (x)

What is the domain of f(x)=(\sqrt[4]{3x-2})/(x-5)+x ?
The domain of f(x)=(\sqrt[4]{3x-2})/(x-5)+x is 2/3 <= x<5\lor x>5