What is the domain of f(x)=(x+3)/(sqrt(6-3x)) ?

The domain of f(x)=(x+3)/(sqrt(6-3x)) is x<2

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domain of f(x)=(x+3)/(sqrt(6-3x))

domain

f (x) = \frac{x + 3}{6 - 3 x}

x < 2

Solution steps

Find non-negative values for radicals:

x \leq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x < 2

f (x) = \frac{2}{x ^{2}}

f (x) = x - 3 - 4

f (x) = lo g_{10} (4 - 2 x)

f (x) = lo g_{10} (16 x - x^{2})

f (x) = \frac{x - 5}{x + 8}

What is the domain of f(x)=(x+3)/(sqrt(6-3x)) ?
The domain of f(x)=(x+3)/(sqrt(6-3x)) is x<2