What is the domain of f(x)=sqrt(2x-6-1) ?

The domain of f(x)=sqrt(2x-6-1) is x>= 7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(2x-6-1)

domain

f (x) = 2 x - 6 - 1

x \geq \frac{7}{2}

Interval Notation

[\frac{7}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{7}{2}

The function domain

x \geq \frac{7}{2}

f (x) = \frac{2 x}{x - 1}

f (x) = \frac{2 x - 4}{x ^{2} - 4 x}

y = \frac{1}{x + 1}

f (x) = \frac{( x - 1 ) ^{2}}{x + 1}

f (x) = \frac{x}{1 - x}

What is the domain of f(x)=sqrt(2x-6-1) ?
The domain of f(x)=sqrt(2x-6-1) is x>= 7/2