What is the domain of f(x)=(2x)/(sqrt(x-1)) ?

The domain of f(x)=(2x)/(sqrt(x-1)) is x>1

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domain of f(x)=(2x)/(sqrt(x-1))

domain

f (x) = \frac{2 x}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

f (x) = \frac{2 x - 4}{x ^{2} - 4 x}

y = \frac{1}{x + 1}

f (x) = \frac{( x - 1 ) ^{2}}{x + 1}

f (x) = \frac{x}{1 - x}

f (x) = \frac{x - 1}{x ^{2} + 9}

What is the domain of f(x)=(2x)/(sqrt(x-1)) ?
The domain of f(x)=(2x)/(sqrt(x-1)) is x>1