What is the domain of f(x)=(x^2+4x)/(3x^2-12) ?

The domain of f(x)=(x^2+4x)/(3x^2-12) is x 2

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domain of f(x)=(x^2+4x)/(3x^2-12)

domain

f (x) = \frac{x ^{2} + 4 x}{3 x ^{2} - 12}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

y - y^{2} + arcsin (y)

f (x) = 4 - t^{2}

y = x^{2} + 2 x + 4

f (x) = \frac{x - 3}{x ^{2} - 49}

lo g_{2} (x + 4)

What is the domain of f(x)=(x^2+4x)/(3x^2-12) ?
The domain of f(x)=(x^2+4x)/(3x^2-12) is x<-2\lor-2<x<2\lor x>2