What is the domain of (x^2-64)/(5x-1) ?

The domain of (x^2-64)/(5x-1) is x 1/5

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domain of (x^2-64)/(5x-1)

domain

\frac{x ^{2} - 64}{5 x - 1}

x < \frac{1}{5} or x > \frac{1}{5}

Interval Notation

(- \infty, \frac{1}{5}) \cup (\frac{1}{5}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{5}

The function domain

x < \frac{1}{5} or x > \frac{1}{5}

- \frac{2}{3} sin (\frac{1}{3}) (y - \frac{3 π}{4}) + 2

x^{4} - 1

f (x) = (1 - x^{2})^{\frac{1}{3}}

\frac{x}{ln ( x )}

f (x) = \frac{2 x - 1}{x ^{2} + 1}

What is the domain of (x^2-64)/(5x-1) ?
The domain of (x^2-64)/(5x-1) is x< 1/5 \lor x> 1/5