What is the domain of f(x)=(1/2)^x-1 ?

The domain of f(x)=(1/2)^x-1 is -infinity <x<infinity

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domain of f(x)=(1/2)^x-1

domain

f (x) = (\frac{1}{2})^{x} - 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

1 + ln (\frac{1 - x}{1 + x})

y = \frac{x}{x ^{2} - 1}

f (x) = 16 x^{2} - 2

f (x) = \frac{3}{- 3 - x}

f (x) = \frac{2 x - 1}{x + 1}

What is the domain of f(x)=(1/2)^x-1 ?
The domain of f(x)=(1/2)^x-1 is -infinity <x<infinity