What is the domain of f(x)=(e^x-1)/(e^x+1) ?

The domain of f(x)=(e^x-1)/(e^x+1) is -infinity <x<infinity

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domain of f(x)=(e^x-1)/(e^x+1)

domain

f (x) = \frac{e ^{x} - 1}{e ^{x} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x ^{2} - 4}{1 - x ^{2}}

f (x) = \frac{( 3 - x )}{( x + 2 )}

\frac{3 x - 5}{x ^{2} - 5 x + 4}

f (x) = - 3.4

\frac{1}{18 - 3 x - x ^{2}}

What is the domain of f(x)=(e^x-1)/(e^x+1) ?
The domain of f(x)=(e^x-1)/(e^x+1) is -infinity <x<infinity