What is the domain of f(x)=(x^2-4)/(1-x^2) ?

The domain of f(x)=(x^2-4)/(1-x^2) is x 1

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domain of f(x)=(x^2-4)/(1-x^2)

domain

f (x) = \frac{x ^{2} - 4}{1 - x ^{2}}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = \frac{( 3 - x )}{( x + 2 )}

\frac{3 x - 5}{x ^{2} - 5 x + 4}

f (x) = - 3.4

\frac{1}{18 - 3 x - x ^{2}}

f (x) = \frac{1}{( x + 5 ) ( x - 2 ) ( x - 7 )}

What is the domain of f(x)=(x^2-4)/(1-x^2) ?
The domain of f(x)=(x^2-4)/(1-x^2) is x<-1\lor-1<x<1\lor x>1