What is the domain of f(x)=sqrt(x^3+8) ?

The domain of f(x)=sqrt(x^3+8) is x>=-2

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domain of f(x)=sqrt(x^3+8)

domain

f (x) = x^{3} + 8

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

f (x) = x^{3} + 5

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 1

f (x) = \frac{x - 1}{x + 2}

f (x) = - 5 x^{2} - 4

f (x) = 3 - 4 - x^{2}

What is the domain of f(x)=sqrt(x^3+8) ?
The domain of f(x)=sqrt(x^3+8) is x>=-2