What is the domain of sin(x),-pi/2 <x< pi/2 ?

The domain of sin(x),-pi/2 <x< pi/2 is -pi/2 <x< pi/2

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domain of sin(x),-pi/2 <x< pi/2

domain

sin (x), - \frac{π}{2} < x < \frac{π}{2}

- \frac{π}{2} < x < \frac{π}{2}

Interval Notation

(- \frac{π}{2}, \frac{π}{2})

Solution steps

Set the domain to the given interval

- \frac{π}{2} < x < \frac{π}{2}

The function has no undefined points nor domain constraints. Therefore, the domain is

- \frac{π}{2} < x < \frac{π}{2}

f (x) = \frac{- 12 ( 3 x ^{2} + 4 )}{( x ^{2} - 4 ) ^{3}}

f (x) = ln (x + x^{2} - 1)

f (x) = \frac{x + 7}{2}

f (x) = lo g_{10} (14 - x)

+ ln (x) + ln (7 - x)

What is the domain of sin(x),-pi/2 <x< pi/2 ?
The domain of sin(x),-pi/2 <x< pi/2 is -pi/2 <x< pi/2