What is the domain of (x^2-9)/(x+3) ?

The domain of (x^2-9)/(x+3) is x -3

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domain of (x^2-9)/(x+3)

domain

\frac{x ^{2} - 9}{x + 3}

x < - 3 or x > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3

The function domain

x < - 3 or x > - 3

∣ 3 - 2 x ∣ - x^{2} - 3 x + 2

f (x) = \frac{2 x - 1}{x ^{2} - 1}

y = \frac{3 x + 4}{- 2 x + 6}

\frac{x ^{2} - 3 x + 2}{x ^{2} - 4}

f (x) = x^{2} + x

What is the domain of (x^2-9)/(x+3) ?
The domain of (x^2-9)/(x+3) is x<-3\lor x>-3