What is the domain of (3x(x-8))/(6x^2-41x-7) ?

The domain of (3x(x-8))/(6x^2-41x-7) is x 7

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domain of (3x(x-8))/(6x^2-41x-7)

domain

\frac{3 x ( x - 8 )}{6 x ^{2} - 41 x - 7}

x < - \frac{1}{6} or - \frac{1}{6} < x < 7 or x > 7

Interval Notation

(- \infty, - \frac{1}{6}) \cup (- \frac{1}{6}, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - \frac{1}{6}

The function domain

x < - \frac{1}{6} or - \frac{1}{6} < x < 7 or x > 7

y = 2 cot (3) (\frac{x - π}{3}) - 2

f (x) = 0. 3^{x - 2} - 4

f (x) = \frac{1 - x ^{2}}{ln ( - x )}

\frac{4 x - 3}{2 x + 1}

f (x) = - 1 - 34 - 2 (- 1)^{2}

What is the domain of (3x(x-8))/(6x^2-41x-7) ?
The domain of (3x(x-8))/(6x^2-41x-7) is x<-1/6 \lor-1/6 <x<7\lor x>7