What is the domain of (4x-3)/(2x+1) ?

The domain of (4x-3)/(2x+1) is x -1/2

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domain of (4x-3)/(2x+1)

domain

\frac{4 x - 3}{2 x + 1}

x < - \frac{1}{2} or x > - \frac{1}{2}

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or x > - \frac{1}{2}

f (x) = - 1 - 34 - 2 (- 1)^{2}

y = \frac{1}{x + 6}

f (x) = 8 + (ln (x^{2} - 9))^{2}

f (x) = 10 x - 2 y = 4

f (x) = \frac{1}{x ^{2} - 1}

What is the domain of (4x-3)/(2x+1) ?
The domain of (4x-3)/(2x+1) is x<-1/2 \lor x>-1/2