What is the domain of f(x)=(sqrt(1-x^2))/(ln(-x)) ?

The domain of f(x)=(sqrt(1-x^2))/(ln(-x)) is -1<x<0

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domain of f(x)=(sqrt(1-x^2))/(ln(-x))

domain

f (x) = \frac{1 - x ^{2}}{ln ( - x )}

- 1 < x < 0

Interval Notation

(- 1, 0)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find positive values for logs:

x < 0

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

- 1 < x < 0

\frac{4 x - 3}{2 x + 1}

f (x) = - 1 - 34 - 2 (- 1)^{2}

y = \frac{1}{x + 6}

f (x) = 8 + (ln (x^{2} - 9))^{2}

f (x) = 10 x - 2 y = 4

What is the domain of f(x)=(sqrt(1-x^2))/(ln(-x)) ?
The domain of f(x)=(sqrt(1-x^2))/(ln(-x)) is -1<x<0