What is the domain of f(x)=8+(ln(x^2-9))^2 ?

The domain of f(x)=8+(ln(x^2-9))^2 is x 3

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domain of f(x)=8+(ln(x^2-9))^2

domain

f (x) = 8 + (ln (x^{2} - 9))^{2}

x < - 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (3, \infty)

Solution steps

Find positive values for logs:

x < - 3 or x > 3

The function domain

x < - 3 or x > 3

f (x) = 10 x - 2 y = 4

f (x) = \frac{1}{x ^{2} - 1}

f (x) = - 3 + lo g_{2} (x + 1)

(\frac{1}{6})^{x}

f (x) = 3 + ln (x)

What is the domain of f(x)=8+(ln(x^2-9))^2 ?
The domain of f(x)=8+(ln(x^2-9))^2 is x<-3\lor x>3