What is the domain of f(x)=sqrt(1/(x^2-1)) ?

The domain of f(x)=sqrt(1/(x^2-1)) is x 1

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domain of f(x)=sqrt(1/(x^2-1))

domain

f (x) = \frac{1}{x ^{2} - 1}

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x < - 1 or x > 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

f (x) = - 3 + lo g_{2} (x + 1)

(\frac{1}{6})^{x}

f (x) = 3 + ln (x)

\frac{x - 6}{2 x + 3}

f (x) = \frac{1 + x - 3 x ^{2}}{x x ^{2} - 4}

What is the domain of f(x)=sqrt(1/(x^2-1)) ?
The domain of f(x)=sqrt(1/(x^2-1)) is x<-1\lor x>1