What is the domain of f(x)= 1/5 x^2 ?

The domain of f(x)= 1/5 x^2 is -infinity <x<infinity

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domain of f(x)= 1/5 x^2

domain

f (x) = \frac{1}{5} x^{2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{2 x + 1}{2 x - 1}

arcsin (\frac{1}{2} 2 - x)

(\frac{x}{2})^{2} + \frac{1}{x}

f (x) = \frac{10}{x} (4 - x)

f (x) = 4 x + 16

What is the domain of f(x)= 1/5 x^2 ?
The domain of f(x)= 1/5 x^2 is -infinity <x<infinity