What is the domain of f(x)= 1/(ln(x+1)) ?

The domain of f(x)= 1/(ln(x+1)) is -1 0

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domain of f(x)= 1/(ln(x+1))

domain

f (x) = \frac{1}{ln ( x + 1 )}

- 1 < x < 0 or x > 0

Interval Notation

(- 1, 0) \cup (0, \infty)

Solution steps

Find positive values for logs:

x > - 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 < x < 0 or x > 0

- (\frac{1}{4})^{x} - 2

\frac{- 2 x ^{2} + 5 x - 1}{2 x - 1}

f (x) = x^{2} - 16 \cdot (x^{2} + x - 2)

\frac{x ^{3} - 27}{x}

x^{2} + 5 x - 6

What is the domain of f(x)= 1/(ln(x+1)) ?
The domain of f(x)= 1/(ln(x+1)) is -1<x<0\lor x>0