What is the domain of h(x)=(x+8)/(x^2-64) ?

The domain of h(x)=(x+8)/(x^2-64) is x 8

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domain of h(x)=(x+8)/(x^2-64)

domain

h (x) = \frac{x + 8}{x ^{2} - 64}

x < - 8 or - 8 < x < 8 or x > 8

Interval Notation

(- \infty, - 8) \cup (- 8, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = - 8

The function domain

x < - 8 or - 8 < x < 8 or x > 8

f (x) = 1 - ∣ 3 x + 2 ∣

f (x) = 3 + 2 x - 1

f (x) = \frac{x}{x ^{2} + 5 x + 6}

f (x) = \frac{3 x - 9}{x - 4}

f (x) = \frac{2 x + 3}{5 x + 4}

What is the domain of h(x)=(x+8)/(x^2-64) ?
The domain of h(x)=(x+8)/(x^2-64) is x<-8\lor-8<x<8\lor x>8