What is the domain of f(x)=sqrt(1-|3x+2|) ?

The domain of f(x)=sqrt(1-|3x+2|) is -1<= x<=-1/3

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domain of f(x)=sqrt(1-|3x+2|)

domain

f (x) = 1 - ∣ 3 x + 2 ∣

- 1 \leq x \leq - \frac{1}{3}

Interval Notation

[- 1, - \frac{1}{3}]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq - \frac{1}{3}

The function domain

- 1 \leq x \leq - \frac{1}{3}

f (x) = 3 + 2 x - 1

f (x) = \frac{x}{x ^{2} + 5 x + 6}

f (x) = \frac{3 x - 9}{x - 4}

f (x) = \frac{2 x + 3}{5 x + 4}

f (x) = \frac{x + 3}{x ^{2} - 5 x}

What is the domain of f(x)=sqrt(1-|3x+2|) ?
The domain of f(x)=sqrt(1-|3x+2|) is -1<= x<=-1/3