What is the domain of f(x)=sqrt(x+1)-1 ?

The domain of f(x)=sqrt(x+1)-1 is x>=-1

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domain of f(x)=sqrt(x+1)-1

domain

f (x) = x + 1 - 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

y = arccos (\frac{1}{x - 3})

f (x) = \frac{2}{1 - cos ( x )}

f (x) = \frac{( 5 ln ( x ) )}{x ^{3}}

\frac{x ^{2} - 2}{x ^{2} - 4}

ln (e^{x} - 8) + 5

What is the domain of f(x)=sqrt(x+1)-1 ?
The domain of f(x)=sqrt(x+1)-1 is x>=-1