What is the domain of f(x)= 8/(sqrt(-6-x)) ?

The domain of f(x)= 8/(sqrt(-6-x)) is x<-6

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domain of f(x)= 8/(sqrt(-6-x))

domain

f (x) = \frac{8}{- 6 - x}

x < - 6

Interval Notation

(- \infty, - 6)

Solution steps

Find non-negative values for radicals:

x \leq - 6

Find undefined (singularity) points:

x = - 6

Combine real regions and undefined points for final function domain

x < - 6

- 1 0^{x + 2} - 3

g (x) = \frac{1}{x ^{2} - x}

f (x) = \frac{( x ^{2} - x - 12 )}{25 - x ^{2}}

ln (8 - x^{3})

f (x) = ln (x^{2} + 2 x - 3)

What is the domain of f(x)= 8/(sqrt(-6-x)) ?
The domain of f(x)= 8/(sqrt(-6-x)) is x<-6