What is the parity y=(1-e^x)^{1/(-e^x)} ?

The parity y=(1-e^x)^{1/(-e^x)} is Neither even nor odd

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parity y=(1-e^x)^{1/(-e^x)}

parity

y = (1 - e^{x})^{\frac{1}{- e ^{x}}}

Neither even nor odd

Solution steps

f (x) : (1 - e^{x})^{- \frac{1}{e ^{x}}}

f (- x) : (1 - e^{- x})^{- e^{x}}

- f (x) : - (1 - e^{x})^{- \frac{1}{e ^{x}}}

Check parity of

(1 - e^{x})^{- \frac{1}{e ^{x}}}

Check if Even:

False

Check if Odd:

False

Neither even nor odd

f (x) = - ln (x)

f (x) = \frac{2 x ^{2} - 14 x + 20}{x ^{2} - 4}

f (x) = 6 x^{4} + 16 x^{3}

f (x) = e^{- x^{2}}

f (x) = 4 x - 12

What is the parity y=(1-e^x)^{1/(-e^x)} ?
The parity y=(1-e^x)^{1/(-e^x)} is Neither even nor odd