What is the domain of f(x)= 4/(3n^2-n-2) ?

The domain of f(x)= 4/(3n^2-n-2) is n 1

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domain of f(x)= 4/(3n^2-n-2)

domain

f (x) = \frac{4}{3 n ^{2} - n - 2}

n < - \frac{2}{3} or - \frac{2}{3} < n < 1 or n > 1

Interval Notation

(- \infty, - \frac{2}{3}) \cup (- \frac{2}{3}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

n = 1, n = - \frac{2}{3}

The function domain

n < - \frac{2}{3} or - \frac{2}{3} < n < 1 or n > 1

f (x) = \frac{1}{t + 7}

f (x) = x^{4} - 16

6^{x} + 2

f (x) = \frac{2 x}{3 x - 4}

X^{2} - 1

What is the domain of f(x)= 4/(3n^2-n-2) ?
The domain of f(x)= 4/(3n^2-n-2) is n<-2/3 \lor-2/3 <n<1\lor n>1