What is the domain of f(y)= 1/(x^2) ?

The domain of f(y)= 1/(x^2) is x 0

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domain of f(y)= 1/(x^2)

domain

f (y) = \frac{1}{x ^{2}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

f (x) = \frac{x ^{2} + 2 x + 1}{x ^{2} - x}

y = \frac{1}{ln ( x )}

f (x) = x + 64

f (x) = \frac{10 x ^{2} + x}{x ^{2} + 8}

f (x) = \frac{( n - 1 ) ( - 1 ) ^{n + 1}}{2 n + 3}

What is the domain of f(y)= 1/(x^2) ?
The domain of f(y)= 1/(x^2) is x<0\lor x>0