What is the domain of f(x)= 1/(x^2-64) ?

The domain of f(x)= 1/(x^2-64) is x 8

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domain of f(x)= 1/(x^2-64)

domain

f (x) = \frac{1}{x ^{2} - 64}

x < - 8 or - 8 < x < 8 or x > 8

Interval Notation

(- \infty, - 8) \cup (- 8, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = - 8

The function domain

x < - 8 or - 8 < x < 8 or x > 8

f (x) = \frac{1}{x ^{2} - 4 x}

- 4 x + 9

f (x) = x^{3} + 3 x^{2} - 25 x - 75

\frac{x ^{2} - 12 x + 32}{x ^{2} - 6 x + 8}

f (x) = \frac{( x - 3 )}{( x + 5 )}

What is the domain of f(x)= 1/(x^2-64) ?
The domain of f(x)= 1/(x^2-64) is x<-8\lor-8<x<8\lor x>8