What is the domain of f(t)=(5t^2-64)/(3t+17) ?

The domain of f(t)=(5t^2-64)/(3t+17) is t -17/3

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domain of f(t)=(5t^2-64)/(3t+17)

domain

f (t) = \frac{5 t ^{2} - 64}{3 t + 17}

t < - \frac{17}{3} or t > - \frac{17}{3}

Interval Notation

(- \infty, - \frac{17}{3}) \cup (- \frac{17}{3}, \infty)

Solution steps

Find undefined (singularity) points:

t = - \frac{17}{3}

The function domain

t < - \frac{17}{3} or t > - \frac{17}{3}

- 2 x - 5

f (x) = \frac{2 - x}{x ^{2} - 4 x + 3}

f (x) = - 5.4

f (x) = 4^{l o g_{2} (16 x) + 1} = 1

f (x) = \frac{( x ^{2} + 1 ) ( x + 1 )}{x - 1}

What is the domain of f(t)=(5t^2-64)/(3t+17) ?
The domain of f(t)=(5t^2-64)/(3t+17) is t<-17/3 \lor t>-17/3