What is the domain of f(x)=4sin^2(x),-pi<= x<= pi ?

The domain of f(x)=4sin^2(x),-pi<= x<= pi is -pi<= x<= pi

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domain of f(x)=4sin^2(x),-pi<= x<= pi

domain

f (x) = 4 sin^{2} (x), - π \leq x \leq π

- π \leq x \leq π

Interval Notation

[- π, π]

Solution steps

Set the domain to the given interval

- π \leq x \leq π

The function has no undefined points nor domain constraints. Therefore, the domain is

- π \leq x \leq π

f (t) = \frac{5 t ^{2} - 64}{3 t + 17}

- 2 x - 5

f (x) = \frac{2 - x}{x ^{2} - 4 x + 3}

f (x) = - 5.4

f (x) = 4^{l o g_{2} (16 x) + 1} = 1

What is the domain of f(x)=4sin^2(x),-pi<= x<= pi ?
The domain of f(x)=4sin^2(x),-pi<= x<= pi is -pi<= x<= pi