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Popular >

extreme (4x^2)/(x^2-25)

Solution

extreme points

\frac{4 x ^{2}}{x ^{2} - 25}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{200 x}{( x ^{2} - 25 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = 0

into

\frac{4 x ^{2}}{x ^{2} - 25} : 0

Maximum (0, 0)

Popular Examples

extreme f(x,y)=x^2-y^2-x-y extreme points

f (x, y) = x^{2} - y^{2} - x - y

extreme f(x,y)=x^3+y^3-3xy+1 extreme points

f (x, y) = x^{3} + y^{3} - 3 x y + 1

extreme f(x)=sqrt(x^2+36)extreme points

f (x) = x^{2} + 36

extreme y=3x^2+12x extreme points

y = 3 x^{2} + 12 x

extreme f(x)=-2x^3+12x^2+18 extreme points

f (x) = - 2 x^{3} + 12 x^{2} + 18

Frequently Asked Questions (FAQ)

What is the extreme (4x^2)/(x^2-25) ?
The extreme (4x^2)/(x^2-25) is Maximum(0,0)