What is the extreme f(x)=x^3-5x^2+3x+10 ?

The extreme f(x)=x^3-5x^2+3x+10 is Maximum(1/3 , 283/27),Minimum(3,1)

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extreme f(x)=x^3-5x^2+3x+10

extreme points

f (x) = x^{3} - 5 x^{2} + 3 x + 10

Maximum (\frac{1}{3}, \frac{283}{27}), Minimum (3, 1)

Solution steps

f^{'} (x) = 3 x^{2} - 10 x + 3

Find intervals:

Increasing

: - \infty < x < \frac{1}{3},

Decreasing

: \frac{1}{3} < x < 3,

Increasing

: 3 < x < \infty

Plug

x = \frac{1}{3}

into

x^{3} - 5 x^{2} + 3 x + 10 : \frac{283}{27}

Maximum (\frac{1}{3}, \frac{283}{27})

Plug

x = 3

into

x^{3} - 5 x^{2} + 3 x + 10 : 1

Minimum (3, 1)

Maximum (\frac{1}{3}, \frac{283}{27}), Minimum (3, 1)

f (x) = e^{- x}

f (x) = 9 x^{\frac{2}{3}} + 3 x - 6

f (x, y) = (x^{2} + y^{2})

f (x) = \frac{x ^{2} - 2 x + 2}{x - 1}

f (x) = 2 x^{3} - 9 x^{2} + 27

What is the extreme f(x)=x^3-5x^2+3x+10 ?
The extreme f(x)=x^3-5x^2+3x+10 is Maximum(1/3 , 283/27),Minimum(3,1)