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Popular >

extreme f(x)=-x^2+2x+3

Solution

extreme points

f (x) = - x^{2} + 2 x + 3

Solution

Maximum (1, 4)

Solution steps

f^{'} (x) = - 2 x + 2

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

- x^{2} + 2 x + 3 : 4

Maximum (1, 4)

Popular Examples

extreme f(x)=x^2-2x-8 extreme points

f (x) = x^{2} - 2 x - 8

extreme f(x)=(-8)/(x^2-4)extreme points

f (x) = \frac{- 8}{x ^{2} - 4}

extreme f(x)=(x^2-x-2)/(x^2-6x+9)extreme points

f (x) = \frac{x ^{2} - x - 2}{x ^{2} - 6 x + 9}

extreme f(x,y)=xy+8/x+8/y extreme points

f (x, y) = x y + \frac{8}{x} + \frac{8}{y}

extreme f(x,y)=xy-7xy+200x extreme points

f (x, y) = x y - 7 x y + 200 x

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+2x+3 ?
The extreme f(x)=-x^2+2x+3 is Maximum(1,4)