What is the extreme f(x)=2x^3-9x^2-24x+1 ?

The extreme f(x)=2x^3-9x^2-24x+1 is Maximum(-1,14),Minimum(4,-111)

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extreme f(x)=2x^3-9x^2-24x+1

extreme points

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 1

Maximum (- 1, 14), Minimum (4, - 111)

Solution steps

f^{'} (x) = 6 x^{2} - 18 x - 24

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 1

into

2 x^{3} - 9 x^{2} - 24 x + 1 : 14

Maximum (- 1, 14)

Plug

x = 4

into

2 x^{3} - 9 x^{2} - 24 x + 1 : - 111

Minimum (4, - 111)

Maximum (- 1, 14), Minimum (4, - 111)

f (x) = \frac{8 x ^{3}}{3} - 5 x^{2} - 3 x + 4

f (x, y) = 6 x^{2} - 2 x^{3} + 3 y^{2} + 6 x y

g (x, y) = x^{3} - 3 x y^{2} + y^{3}

f (x) = x^{2} + x

f (x) = \frac{x}{x ^{2} - x + 4}, 0 \leq x \leq 6

What is the extreme f(x)=2x^3-9x^2-24x+1 ?
The extreme f(x)=2x^3-9x^2-24x+1 is Maximum(-1,14),Minimum(4,-111)