What is the extreme f(x)=(x^3)/3-x^2-3x ?

The extreme f(x)=(x^3)/3-x^2-3x is Maximum(-1, 5/3),Minimum(3,-9)

Popular >

extreme f(x)=(x^3)/3-x^2-3x

extreme points

f (x) = \frac{x ^{3}}{3} - x^{2} - 3 x

Maximum (- 1, \frac{5}{3}), Minimum (3, - 9)

Solution steps

f^{'} (x) = x^{2} - 2 x - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

\frac{x ^{3}}{3} - x^{2} - 3 x : \frac{5}{3}

Maximum (- 1, \frac{5}{3})

Plug

x = 3

into

\frac{x ^{3}}{3} - x^{2} - 3 x : - 9

Minimum (3, - 9)

Maximum (- 1, \frac{5}{3}), Minimum (3, - 9)

f (x) = \frac{2 x}{x ^{2} - 9}

f (x, y) = y^{3} + 3 x^{2} y - 6 x^{2} - 6 y^{2} + 2

f (x, y) = 4 x y - x^{4} - 2 y^{2}

f (x, y) = 4 x^{2} + 2 y^{2} - 2 x y - 10 y - 2 x

(x - y) (9 - x y)

What is the extreme f(x)=(x^3)/3-x^2-3x ?
The extreme f(x)=(x^3)/3-x^2-3x is Maximum(-1, 5/3),Minimum(3,-9)