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Popular >

extreme f(x)=x^2-8x+12

Solution

extreme points

f (x) = x^{2} - 8 x + 12

Solution

Minimum (4, - 4)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x + 12 : - 4

Minimum (4, - 4)

Popular Examples

extreme f(x)=x^3-3x^2-9x+7 extreme points

f (x) = x^{3} - 3 x^{2} - 9 x + 7

extreme f(x)=x^3-3x^2-9x+4 extreme points

f (x) = x^{3} - 3 x^{2} - 9 x + 4

extreme x/(ln(x))extreme points

\frac{x}{ln ( x )}

extreme f(x)=x^3-3xy-y^2 extreme points

f (x) = x^{3} - 3 x y - y^{2}

extreme f(x)=x^2-4x+2 extreme points

f (x) = x^{2} - 4 x + 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-8x+12 ?
The extreme f(x)=x^2-8x+12 is Minimum(4,-4)