What is the extreme f(x)=(x+1)^2(x-2) ?

The extreme f(x)=(x+1)^2(x-2) is Maximum(-1,0),Minimum(1,-4)

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extreme f(x)=(x+1)^2(x-2)

extreme points

f (x) = (x + 1)^{2} (x - 2)

Maximum (- 1, 0), Minimum (1, - 4)

Solution steps

f^{'} (x) = 3 (x + 1) (x - 1)

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

(x + 1)^{2} (x - 2) : 0

Maximum (- 1, 0)

Plug

x = 1

into

(x + 1)^{2} (x - 2) : - 4

Minimum (1, - 4)

Maximum (- 1, 0), Minimum (1, - 4)

f (x) = \frac{( 3 x - 57 )}{( x - 85 ) ^{7}}

f (x, y) = 3 - 25 - (x + 1)^{2} - (y - 1)^{2}

f (x, y) = - 2 x^{2} + 3 x y - y^{2} + x + y

f (x) = ln (2 + sin (x))

f (x) = x + ln (x^{2} - 3)

What is the extreme f(x)=(x+1)^2(x-2) ?
The extreme f(x)=(x+1)^2(x-2) is Maximum(-1,0),Minimum(1,-4)