What is the extreme f(x,y)=-2x^2+3xy-y^2+x+y ?

The extreme f(x,y)=-2x^2+3xy-y^2+x+y is Saddle(-5,-7)

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extreme f(x,y)=-2x^2+3xy-y^2+x+y

extreme points

f (x, y) = - 2 x^{2} + 3 x y - y^{2} + x + y

Saddle (- 5, - 7)

Solution steps

Find the critical points:

(- 5, - 7)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(- 5, - 7) :

Saddle

Saddle (- 5, - 7)

f (x) = ln (2 + sin (x))

f (x) = x + ln (x^{2} - 3)

f (x y) = 2 x^{2} - 8 x + y^{2} + 16 y + 100

g (x) = 2 x^{3} + 3 x^{2} + 12 x - 4

f (x) = x^{3} - 10 x^{2} + 33 x - 36

What is the extreme f(x,y)=-2x^2+3xy-y^2+x+y ?
The extreme f(x,y)=-2x^2+3xy-y^2+x+y is Saddle(-5,-7)