What is the extreme f(x,y)=2*((x^2-2*x+3))/(y*(y+2)) ?

The extreme f(x,y)=2*((x^2-2*x+3))/(y*(y+2)) is None

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extreme f(x,y)=2((x^2-2x+3))/(y*(y+2))

extreme points

f (x, y) = 2 \cdot \frac{( x ^{2} - 2 \cdot x + 3 )}{y \cdot ( y + 2 )}

None

Solution steps

Find the critical points:

None

2 \cdot \frac{x ^{2} - 2 \cdot x + 3}{y \cdot ( y + 2 )}

has no critical points, therefore there are no extreme points

None

f (x) = x^{y}

f (x) = 4

2 x^{3} - 3 x^{2} - 36 x + 5

6 x^{2} - 2 x^{3} + 3 y^{2} + 6 x y

f (x, y) = 2 x^{3} y^{2} + 4 x y + 6

What is the extreme f(x,y)=2*((x^2-2*x+3))/(y*(y+2)) ?
The extreme f(x,y)=2*((x^2-2*x+3))/(y*(y+2)) is None