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Popular >

extreme (2x^2-2)/(x^2-4)

Solution

extreme points

\frac{2 x ^{2} - 2}{x ^{2} - 4}

Solution

Maximum (0, \frac{1}{2})

Solution steps

f^{'} (x) = - \frac{12 x}{( x ^{2} - 4 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 0

into

\frac{2 x ^{2} - 2}{x ^{2} - 4} : \frac{1}{2}

Maximum (0, \frac{1}{2})

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Frequently Asked Questions (FAQ)

What is the extreme (2x^2-2)/(x^2-4) ?
The extreme (2x^2-2)/(x^2-4) is Maximum(0, 1/2)