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Popular >

extreme y=x^3-3x+5

Solution

extreme points

y = x^{3} - 3 x + 5

Solution

Maximum (- 1, 7), Minimum (1, 3)

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x + 5 : 7

Maximum (- 1, 7)

Plug

x = 1

into

x^{3} - 3 x + 5 : 3

Minimum (1, 3)

Maximum (- 1, 7), Minimum (1, 3)

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extreme f(x)=x-ln(x), 1/2 <= x<= 2 extreme points

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extreme f(x,y)=9x^2+18xy+y^3 extreme points

f (x, y) = 9 x^{2} + 18 x y + y^{3}

extreme f(x)=2x^2+3x-5 extreme points

f (x) = 2 x^{2} + 3 x - 5

extreme f(x)=x^3-12x-10 extreme points

f (x) = x^{3} - 12 x - 10

Frequently Asked Questions (FAQ)

What is the extreme y=x^3-3x+5 ?
The extreme y=x^3-3x+5 is Maximum(-1,7),Minimum(1,3)