What is the extreme f(x)=(4-2)(4-6)^3+8 ?

The extreme f(x)=(4-2)(4-6)^3+8 is None

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extreme f(x)=(4-2)(4-6)^3+8

extreme points

f (x) = (4 - 2) (4 - 6)^{3} + 8

None

Solution steps

Find the critical points:

None

(4 - 2) (4 - 6)^{3} + 8

has no critical points, therefore there are no extreme points

None

y = \frac{x ^{2} - 4}{x ^{2} + 4}

f (x) = x^{2} - 12 x + 6

f (x) = x^{2} - 12 x + 7

f (x) = - x^{3} + 3 x^{2} + 5

x^{5} - 5 x^{3} - 20 x - 2

What is the extreme f(x)=(4-2)(4-6)^3+8 ?
The extreme f(x)=(4-2)(4-6)^3+8 is None