What is the extreme f(x)=2x+7x^{2/7} ?

The extreme f(x)=2x+7x^{2/7} is Minimum(-1,5),Maximum(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x+7x^{2/7}

extreme points

f (x) = 2 x + 7 x^{\frac{2}{7}}

Minimum (- 1, 5), Maximum (0, 0)

Solution steps

f^{'} (x) = 2 + \frac{2}{x ^{\frac{5}{7}}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

2 x + 7 x^{\frac{2}{7}} : 5

Minimum (- 1, 5)

Plug

x = 0

into

2 x + 7 x^{\frac{2}{7}} : 0

Maximum (0, 0)

Minimum (- 1, 5), Maximum (0, 0)

2 x^{3} - 9 x^{2} + 12 x - 6

f (x) = x^{3} - x^{2} - x + 8

f (x) = x^{3} - 6 x^{2} + 12 x - 11

g (x) = \frac{3}{2} x^{2} + 6 x + 4

f (x, y) = x^{2} y^{2} - 4 x^{2} - y^{2} + 25

What is the extreme f(x)=2x+7x^{2/7} ?
The extreme f(x)=2x+7x^{2/7} is Minimum(-1,5),Maximum(0,0)