What is the extreme f(x)=x^3-x^2-x+8 ?

The extreme f(x)=x^3-x^2-x+8 is Maximum(-1/3 , 221/27),Minimum(1,7)

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extreme f(x)=x^3-x^2-x+8

extreme points

f (x) = x^{3} - x^{2} - x + 8

Maximum (- \frac{1}{3}, \frac{221}{27}), Minimum (1, 7)

Solution steps

f^{'} (x) = 3 x^{2} - 2 x - 1

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

x^{3} - x^{2} - x + 8 : \frac{221}{27}

Maximum (- \frac{1}{3}, \frac{221}{27})

Plug

x = 1

into

x^{3} - x^{2} - x + 8 : 7

Minimum (1, 7)

Maximum (- \frac{1}{3}, \frac{221}{27}), Minimum (1, 7)

f (x) = x^{3} - 6 x^{2} + 12 x - 11

g (x) = \frac{3}{2} x^{2} + 6 x + 4

f (x, y) = x^{2} y^{2} - 4 x^{2} - y^{2} + 25

K (r, s) = 7 r - s

f (x) = 2 sin (∣ x ∣), - 2 π \leq x \leq 2 π

What is the extreme f(x)=x^3-x^2-x+8 ?
The extreme f(x)=x^3-x^2-x+8 is Maximum(-1/3 , 221/27),Minimum(1,7)