What is the extreme f(x)=x^3-x^2-x-10 ?

The extreme f(x)=x^3-x^2-x-10 is Maximum(-1/3 ,-265/27),Minimum(1,-11)

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extreme f(x)=x^3-x^2-x-10

extreme points

f (x) = x^{3} - x^{2} - x - 10

Maximum (- \frac{1}{3}, - \frac{265}{27}), Minimum (1, - 11)

Solution steps

f^{'} (x) = 3 x^{2} - 2 x - 1

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

x^{3} - x^{2} - x - 10 : - \frac{265}{27}

Maximum (- \frac{1}{3}, - \frac{265}{27})

Plug

x = 1

into

x^{3} - x^{2} - x - 10 : - 11

Minimum (1, - 11)

Maximum (- \frac{1}{3}, - \frac{265}{27}), Minimum (1, - 11)

y = 2 x^{3} + 3 x^{2} - 36 x + 4

f (x, y) = - 2 x^{2} + 5 x y - 3 y^{2} + x + y

f (x) = \frac{5 x - 2}{x ^{2} - 10 x + 25}

p (a, c) = a + 5 + c

f (x) = \frac{( e ^{x^{2}} + e ^{2 - x^{2}} )}{5}

What is the extreme f(x)=x^3-x^2-x-10 ?
The extreme f(x)=x^3-x^2-x-10 is Maximum(-1/3 ,-265/27),Minimum(1,-11)