What is the extreme y=2x^3-21x^2+60x+4 ?

The extreme y=2x^3-21x^2+60x+4 is Maximum(2,56),Minimum(5,29)

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extreme y=2x^3-21x^2+60x+4

extreme points

y = 2 x^{3} - 21 x^{2} + 60 x + 4

Maximum (2, 56), Minimum (5, 29)

Solution steps

f^{'} (x) = 6 x^{2} - 42 x + 60

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 2

into

2 x^{3} - 21 x^{2} + 60 x + 4 : 56

Maximum (2, 56)

Plug

x = 5

into

2 x^{3} - 21 x^{2} + 60 x + 4 : 29

Minimum (5, 29)

Maximum (2, 56), Minimum (5, 29)

f (x) = (x + 1)^{5} - 5 x - 3

a^{3} y = x^{2} (2 a^{2} x^{2})

f (x, y) = x^{3} - 15 x y + y^{3}

f (x) = x^{3} - 5 x^{2} - 8 x + 3

f (x) = 2 x^{2} + 3 y^{2} - 4 x - 12 y + 13

What is the extreme y=2x^3-21x^2+60x+4 ?
The extreme y=2x^3-21x^2+60x+4 is Maximum(2,56),Minimum(5,29)