What is the critical f(x)=sec(x) ?

The critical f(x)=sec(x) is x=2pin,x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=sec(x)

critical points

f (x) = sec (x)

x = 2 πn, x = π + 2 πn

Solution steps

sec (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{2} + 2 πn, x = \frac{π}{2} + 2 πn

Identify critical points not in

f (x)

domain

Domain of

sec (x) : 2 πn \leq x < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < x < \frac{3 π}{2} + 2 πn or \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

sec (x)

is not defined at

x = \frac{3 π}{2} + 2 πn, x = \frac{π}{2} + 2 πn

, therefore:

x = 2 πn, x = π + 2 πn

f (x) = x^{2} - 9

f (x) = \frac{x}{( x - 1 ) ^{2}}

f (x) = x^{4} + 2 x^{3} - 2 x^{2} + 4

\frac{x}{x ^{2} - 9}

y = x^{3} + 9 x^{2} + b