What is the critical f(x)=x^4+2x^3-2x^2+4 ?

The critical f(x)=x^4+2x^3-2x^2+4 is x=-2,x=0,x= 1/2

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critical f(x)=x^4+2x^3-2x^2+4

critical points

f (x) = x^{4} + 2 x^{3} - 2 x^{2} + 4

x = - 2, x = 0, x = \frac{1}{2}

Solution steps

x^{4} + 2 x^{3} - 2 x^{2} + 4

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

x^{4} + 2 x^{3} - 2 x^{2} + 4 : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = \frac{1}{2}

\frac{x}{x ^{2} - 9}

y = x^{3} + 9 x^{2} + b

f (x, y) = x^{3} + y^{3} - x y

f (x, y) = - x^{4} - 32 x + y^{3} - 12 y + 7

f (x) = \frac{x - 4}{- 4 x ^{2} + 4}

What is the critical f(x)=x^4+2x^3-2x^2+4 ?
The critical f(x)=x^4+2x^3-2x^2+4 is x=-2,x=0,x= 1/2