What is the inverse of f(x)=x^2+x+6 ?

The inverse of f(x)=x^2+x+6 is (-1+sqrt(4x-23))/2 ,(-1-sqrt(4x-23))/2

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inverse of f(x)=x^2+x+6

inverse

f (x) = x^{2} + x + 6

\frac{- 1 + 4 x - 23}{2}, \frac{- 1 - 4 x - 23}{2}

Solution steps

y = x^{2} + x + 6

Replace

x

with

y

x = y^{2} + y + 6

Solve for

y, x = y^{2} + y + 6

\frac{- 1 + 4 x - 23}{2}, \frac{- 1 - 4 x - 23}{2}

9 cos (\frac{1}{3} x + \frac{3}{4})

f (x) = x^{3} - 3 x^{2} + 4

\frac{x}{x ^{2} + 243}

y = 7 x

f (x) = (x + 2)^{\frac{2}{3}}

What is the inverse of f(x)=x^2+x+6 ?
The inverse of f(x)=x^2+x+6 is (-1+sqrt(4x-23))/2 ,(-1-sqrt(4x-23))/2