What is the inverse of f(x)=-2(x+3)^2-1 ?

The inverse of f(x)=-2(x+3)^2-1 is sqrt(-(x+1)/2)-3,-sqrt(-(x+1)/2)-3

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inverse of f(x)=-2(x+3)^2-1

inverse

f (x) = - 2 (x + 3)^{2} - 1

- \frac{x + 1}{2} - 3, - - \frac{x + 1}{2} - 3

Solution steps

y = - 2 (x + 3)^{2} - 1

Replace

x

with

y

x = - 2 (y + 3)^{2} - 1

Solve for

y, x = - 2 (y + 3)^{2} - 1

- \frac{x + 1}{2} - 3, - - \frac{x + 1}{2} - 3

(2 x - 8)^{\frac{2}{3}}

f (x) = \frac{( 3 x - 3 )}{x + 6}

- x^{2} + 2 x - 1

(- 1, 1), (- 2, - 1)

6 x - x^{2} - 5

What is the inverse of f(x)=-2(x+3)^2-1 ?
The inverse of f(x)=-2(x+3)^2-1 is sqrt(-(x+1)/2)-3,-sqrt(-(x+1)/2)-3