What is the critical f(x)= x/(x^2+5x+4) ?

The critical f(x)= x/(x^2+5x+4) is x=-2,x=2

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critical f(x)= x/(x^2+5x+4)

critical points

f (x) = \frac{x}{x ^{2} + 5 x + 4}

x = - 2, x = 2

Solution steps

\frac{x}{x ^{2} + 5 x + 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2, x = - 4, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 5 x + 4} : x < - 4 or - 4 < x < - 1 or x > - 1

\frac{x}{x ^{2} + 5 x + 4}

is not defined at

x = - 4, x = - 1

, therefore:

x = - 2, x = 2

f (x) = x^{2} + 8

f (x) = e^{x} (2 x^{2} + x - 8)

\frac{x ^{3}}{3} + \frac{3}{2} y^{2} + 3 x y + 2 x + 6

f (x) = 3 x^{3} - 3 x^{2} - 3 x - 1

What is the critical f(x)= x/(x^2+5x+4) ?
The critical f(x)= x/(x^2+5x+4) is x=-2,x=2